Lonetree is a census-designated place (CDP) in Uinta County, Wyoming, United States. The population was 61 at the 2000 census.
Lonetree is located at 41°2′9″N 110°9′44″W / 41.03583°N 110.16222°W / 41.03583; -110.16222 (41.035734, -110.162226).
According to the United States Census Bureau, the CDP has a total area of 45.6 square miles (118.2 km²), of which, 45.6 square miles (118.1 km²) of it is land and 0.04 square miles (0.1 km²) of it (0.04%) is water.
As of the census of 2000, there were 61 people, 16 households, and 15 families residing in the CDP. The population density was 1.3 people per square mile (0.5/km²). There were 25 housing units at an average density of 0.5/sq mi (0.2/km²). The racial makeup of the CDP was 100.00% White.
There were 16 households out of which 50.0% had children under the age of 18 living with them, 81.3% were married couples living together, 6.3% had a female householder with no husband present, and 6.3% were non-families. No households were made up…
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